［更难题】怎样用3个2完成满足1到20的算式？

jimofc

2-2/2
2-2+2
2+2/2
2+sqr(2+2)
sqr((not(2+2))^2)
2+2+2
2-(not (2+2))
2*2*2
(not 2)^sqr(2+2)
2*(2-not 2)
2+(not 2)^2
(2+2)!/2
|not((not 2)^2)+not 2|
not ((2-not 2)*not 2)
(not (2+2))*not 2
(2+2)^2
not(|2*not 2|*not 2)
2*(not 2)^2
not 2*(not (not 2)^2)
|2*(not (not 2)^2)|