偷来的，顶层复原公式

LL4100

注：1）code p1意是思公式代号(在盲拧中，我们会用到)； occurs:16/288是可能发生这种情况的概率；

code: P1occurs: 16/288 F'LF'R2FL'F'R2F2 (9,12)
code: P2occurs: 16/288 FR'FL2F'RFL2F2 (9,12)
code: P3occurs: 8/288 LU'RD2R'UL'RU'LD2L'UR' (14,16)
code: P4occurs: 8/288 M2DS2D'SM2S' (7,18)
code: P5occurs: 4/288 L'R'U2LRFBU2F'B' (10,12)
code: P6occurs: 16/288 R2U'S'U2SU'R2 (7,12)
code: P7occurs: 16/288 R2US'U2SUR2 (7,12)
code: P8occurs: 16/288 R'L'U2LUL'U2RU'LU (11,13)
code: P9occurs: 16/288 LRU2R'U'RU2L'UR'U' (11,13)
code: P10occurs: 16/288 UR2U'R2DB2L2UL2D'B2 (11,17)
code: P11occurs: 16/288 R'U2RU'F'LFR'F'L'FU'RU' (14,15)
code: P12occurs: 16/288 LU2L'UFR'F'LFRF'UL'U (14,15)
code: P13occurs: 16/288 R'URU'R2F'U'FURFR'F'R2U' (15,17)
code: P14occurs: 16/288 L'R'U2LRFU'BU2F'UB'(U') (12/13,15)
  code: P15occurs: 16/288 LRU2L'R'F'UB'U2FU'B(U) (12/13,15)
code: P16occurs: 16/288 R'UL'U2RU'LFBU2F'B'U' (13,15)
code: P17occurs: 16/288 LU'RU2L'UR'F'B'U2FBU (13,15)
code: P18occurs: 16/288 RU'RUFD'FDF2RFR'F'R' (14,15)
code: P19occurs: 4/288 LU'RU2L'UR'LU'RU2L'UR'U (15,17)
code: P20occurs: 4/288 R'UL'U2RU'LR'UL'U2RU'LU' (15,17)
code: P21occurs: 16/288 y2 FRU'R'FDR'B'R'BR2D'F2 (13,15)

LL4100

怎么图不见了，，第一次失败了

机器贝尔

PLL？而且多不顺手，坐等楼主解释.


虽然步数很少，但是实在不顺手啊

[ 本帖最后由 机器贝尔 于 2010-12-15 17:54 编辑 ]

Xwam

学习一下了，貌似LZ还没发完的说~~

kattokid

这些是？盲拧的公式？不解…

丘比特

为什么我看不懂呢   没图么？…

Cielo

这些PLL公式应该也不是最少步数的吧？