魔方吧·中文魔方俱乐部
标题:
两个公式实现同面任意三角的顺翻或逆翻
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作者:
szlgmjf
时间:
2008-7-22 12:02:16
标题:
两个公式实现同面任意三角的顺翻或逆翻
<P><FONT face=宋体 color=black>练习翻角时发现两个公式可实现同面任意三角的顺翻或逆翻,如下:</FONT></P>
<P><FONT face=宋体 color=black></FONT> </P>
<P><FONT face=宋体 color=black>角编码按老大教程的方法</FONT></P>
<P><FONT face=宋体 color=black></FONT> </P>
<P><FONT face=宋体><FONT color=black>顺翻公式 RUR'<U>U'</U> 以下用<SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">①表示</SPAN></FONT></FONT></P>
<P><SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><FONT color=black>逆翻公式 R<U>U'</U>R'U 以下用<SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">②表示</SPAN></FONT></SPAN></P>
<P><SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><FONT color=black></FONT></SPAN></SPAN> </P><SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">同面任意</SPAN><SPAN lang=EN-US><FONT face="Times New Roman">3</FONT></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">角顺翻公式(以下是底面的角,魔方整体翻转可实现任意面到底面)</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN lang=EN-US style="FONT-FAMILY: 宋体">567</SPAN><SPAN style="FONT-FAMILY: 宋体">角:<SPAN lang=EN-US>D</SPAN>+(①×<SPAN lang=EN-US>2</SPAN>+<SPAN lang=EN-US>D</SPAN>)×<SPAN lang=EN-US>3<SPAN style="mso-spacerun: yes"> </SPAN></SPAN></SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体"><SPAN lang=EN-US><SPAN style="mso-spacerun: yes"></SPAN></SPAN></SPAN></FONT><FONT color=black><SPAN lang=EN-US style="FONT-FAMILY: 宋体">568</SPAN><SPAN style="FONT-FAMILY: 宋体">角:(①×<SPAN lang=EN-US>2</SPAN>+<SPAN lang=EN-US>D</SPAN>)×<SPAN lang=EN-US>3</SPAN>+<SPAN lang=EN-US>D<SPAN style="mso-spacerun: yes"> </SPAN><SPAN style="mso-spacerun: yes"> </SPAN></SPAN>注:即<SPAN lang=EN-US>567</SPAN>角公式的<SPAN lang=EN-US>D</SPAN>放到最后</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体"></SPAN></FONT><FONT color=black><SPAN lang=EN-US style="FONT-FAMILY: 宋体">578</SPAN><SPAN style="FONT-FAMILY: 宋体">角:<SPAN lang=EN-US>D’</SPAN>+(①×<SPAN lang=EN-US>2</SPAN>+<SPAN lang=EN-US>D’</SPAN>)×<SPAN lang=EN-US>3<SPAN style="mso-spacerun: yes"> </SPAN></SPAN>注:即<SPAN lang=EN-US>567</SPAN>角公式的<SPAN lang=EN-US>D</SPAN>换成<SPAN lang=EN-US>D’</SPAN></SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体"><SPAN lang=EN-US></SPAN></SPAN></FONT><FONT color=black><SPAN lang=EN-US style="FONT-FAMILY: 宋体">678</SPAN><SPAN style="FONT-FAMILY: 宋体">角:<SPAN lang=EN-US>2D</SPAN>+(①×<SPAN lang=EN-US>2</SPAN>+<SPAN lang=EN-US>D</SPAN>)×<SPAN lang=EN-US>2</SPAN>+①×<SPAN lang=EN-US>2 <SPAN style="mso-spacerun: yes"> </SPAN></SPAN>注:即<SPAN lang=EN-US>567</SPAN>角公式的最后一个<SPAN lang=EN-US>D</SPAN>放到前面</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体"></SPAN></FONT> </P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体">把上术公式的</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">①换成②,可实现</SPAN><SPAN style="FONT-FAMILY: 宋体">同面任意<SPAN lang=EN-US>3</SPAN>角的逆翻。</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体"></SPAN></FONT><FONT color=black><SPAN lang=EN-US style="FONT-FAMILY: 宋体">Gun</SPAN><SPAN style="FONT-FAMILY: 宋体">的公式,很好记!很顺手!</SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT color=black><SPAN style="FONT-FAMILY: 宋体"></SPAN></FONT><SPAN style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><FONT color=black>再把<SPAN lang=EN-US>D </SPAN>的顺序调换一下,可实现同面任意两角的一逆一顺翻转。</FONT></SPAN></SPAN></SPAN></P>
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本帖最后由 szlgmjf 于 2008-7-23 11:22 编辑
]
作者:
ZJY
时间:
2008-7-22 12:06:15
什么意思?不太明白。
作者:
hzhenr
时间:
2008-7-22 12:12:38
快点整理呀...............
作者:
leejjhhh666
时间:
2008-7-22 12:14:02
标题:
两个公式实现同面任意三角的顺翻或逆翻
应该是下面两个吧
三角翻公式(2个)(同顺或同逆)
2 3 4位都是顺时针翻角
[(R F-R-F)*2+U ] *3 +U
2 3 4位都是逆时针翻角
[(F-R F R-)*2+U ] *3 +U
作者:
melbourne2006
时间:
2008-7-22 12:30:22
其实我觉得还是立<IMG alt="" src="http://bbs.mf8-china.com/images/smilies/default/lol.gif" border=0 smilieid="12"> 体的三角 同时翻比较麻烦。。就是 SET UP 比如138..136..等等的同时逆翻 和顺翻
作者:
szlgmjf
时间:
2008-7-22 12:31:44
标题:
回复 4# 的帖子
比这个随手得多~~~~
作者:
kexin_xiao
时间:
2008-7-22 12:46:03
等待LZ整理好发上来看看
作者:
hzhenr
时间:
2008-7-22 13:04:49
这个是利用FSC的原理吧
作者:
apmkeke
时间:
2008-7-22 13:09:18
o 这样啊~是的 现在试试~
作者:
jerold
时间:
2008-7-22 14:03:03
打完雷,啥时候下雨????
作者:
szlgmjf
时间:
2008-7-23 10:55:25
标题:
回复 9# 的帖子
已经下雨了,请看编辑后的。
作者:
浮云
时间:
2008-7-23 11:43:59
这个就是常说的FSC(FINGER SHORT CUT?)两次可以原地转动ULB角和DRF角啊
作者:
bbshanwei
时间:
2008-7-24 21:32:33
LZ还真是有心,继续研究吧。
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