<P>这是内核球(代号6)：</P>
<P><a href="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/2005217171033235.gif" target="_blank" ><IMG src="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/2005217171033235.gif" border=0></A></P>
<P>接着在球面周围装上8个这种可垂直转动的的块(代号14)：</P>
<P><a href="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/200521717950854.gif" target="_blank" ><IMG src="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/200521717950854.gif" border=0></A></P>
<P>然后在块之间卡上弧型条状轨道(代号5，也8个)：</P>
<P><a href="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/200521717842678.gif" target="_blank" ><IMG src="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/200521717842678.gif" border=0></A></P>
<P>最后再盖上代号30(也是8个)，由于代号30的块与代号14的块相嵌成一个整体(相嵌处是在17与31)，这样这3*8=24个块就聚而不散了，就完成了8个球瓣垂直旋转的结构了。(垂直转动时有四组的30与14的块在转，同时这四组间的3个弧型条状轨道5也在转，这是最秒之处了!)</P>
<P><a href="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/20052171775895.gif" target="_blank" ><IMG src="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/20052171775895.gif" border=0></A></P>
<P>最后在代号30的块的轨道上装最外层的块代号40，就完成了主体结构了。</P>
<P><a href="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/200521717652188.gif" target="_blank" ><IMG src="http://bbs.mf8-china.com/data/attachment/forum/dvbbs/2005-2/200521717652188.gif" border=0></A></P>
<P>其它的都是细节的结构了。</P>
<P>此结构与轨道结构的二阶魔方的构成有相似之处，确实很巧妙的! </P>
[此贴子已经被作者于2005-3-10 13:20:09编辑过] <P>这个魔方的内部结构确实很巧妙，难度比还原六面魔方还要难，表面的直观不去说它了。</P><P>内部结构真是做的复杂，就是有图纸也能以看懂，但对于图纸仅仅懂点皮毛，原来的想法是在垂直转动时用的水平方向的八个轴，因为夹角为45度，会造成相邻轴的切割。这样一想就一直想不通了，昨天晚上听了大烟头的看法，粗步认为内部也不是一个轴结构，也是一个更小一点的球体，表面做有轨道，八个孤面的块中心与内球面的轨道镶嵌，相对来说转动孤面块与内球面相贴，所谓的轴心在内球面上变动位置，只有当八个孤面块方向一致时，八个轴心才在一个水平面上。</P><P>不知道我的想法是不是正确，很想听各位朋友的看法。但要把这个东西做出来真不容易。</P>
masterball
<P>这种魔球的还原是很容易的,最容易掌握的就只用一个公式就行了,那就是等势位相邻的两个块的交换公式:</P><P>f - r1<SUP><FONT color=#ff0000 size=4>-1 </FONT></SUP>- f - r1 - r4 - f - r4<SUP><FONT color=#ff0000 size=4>-1</FONT></SUP> - f<FONT color=#ff0000 size=4><FONT color=#000000 size=3> (f就是指沿中间的白色经线转180度,r1~r4指4层)</FONT></FONT></P>
<P></P>
<P>同理,2,3层只用将上述公式中的r1 ,r4换成r2,r3即可.</P>
<P></P>
<P> 还原步骤如下: 总体上按照先两极,再中间的方法进行。首先是拼好第一层，再找两个用于交换的块（习惯是先拼好有masterball字样的第一层，再以有此图案的那一块和它左边那一块中间纬线为旋转轴）；用上述公式将第四层拼好。然后将中间两层的块放到应该放的层上，水平位置不论，只要块所在层对了即可，然后分别用公式转好第2层和第3层。</P>
<P> 也许到最后有可能遇到有两个相邻块错位的奇偶问题,此时只要将错的那两个放在第3层,将前两层当作是1层与第四层交换即可.<br></P>
[此贴子已经被作者于2006-2-25 22:55:59编辑过]
<P>嗯，这魔球确实会出现两个块对换的现象。</P>
<P>今天我发些拆解图片：</P>
<BR><BR> <BR><BR><BR> <BR><BR> <P>我的拆法是错开轨道旋开来的，装的时候也是两头对准轨道转进去的，对魔方没损伤的，不过这种拆法是技巧的。我对二阶魔方拆法也是这样的。</P>
<P>呵，想拆的魔友要有思想准备，拆坏了可别找我哦。</P>
<P><BR><BR></P> <p>有解的方法吗？</p><p></p> <p><font face="Arial" size="2"><b>Phase 1:</b> Put pieces in their correct layers.</font></p><ol><li><font face="Arial" size="2">Find any piece in the top hemisphere (cap or band) that is not in the correct layer.</font>
</li><li><font face="Arial" size="2">Hold that piece at the front, just to the left of the seam. (On the Logi-Vip sphere, you probably have to turn the layer to get it there.)</font>
</li><li><font face="Arial" size="2">Find a piece in the opposite layer that does not belong there.</font>
</li><li><font face="Arial" size="2">Turn that opposite layer until the wrong piece lies at the front, just to the right of the seam.</font>
</li><li><font face="Arial" size="2">Do this sequence: <br/>1. Twist the right hand side of the ball. <br/>2. Shift the layer containing the two pieces to the right, so both pieces cross the seam. <br/>3. Twist the right hand side of the ball again.</font>
</li><li><font face="Arial" size="2">Repeat a-e until all the pieces are in the correct layer.</font>
</li></ol><p><font face="Arial" size="2"><b>Phase 2:</b> Solve two opposite layers.</font></p><ol type="a"><li><font face="Arial" size="2">Find in any layer two adjacent pieces that you want to swap.</font>
</li><li><font face="Arial" size="2">Hold those pieces at the front, one on each side of the seam. (On the Logi-Vip sphere, you probably have to turn the layer to get them there.)</font>
</li><li><font face="Arial" size="2">Find any two adjacent pieces in the opposite layer that you also want to swap.</font>
</li><li><font face="Arial" size="2">Rotate that layer to bring them to the front, too.</font>
</li><li> <font face="Arial" size="2">Do the following sequence: <br/>1. Twist the right hand side of the ball. <br/>2. Shift the top layer to the right. <br/>3. Twist the right hand side of the ball. <br/>4. Shift the top layer to the left. <br/>5. Shift the bottom layer to the right. <br/>6. Twist the right hand side of the ball. <br/>7. Shift the bottom layer to the left. <br/>8. Twist the right hand side of the ball.</font>
</li><li><font face="Arial" size="2">Continue using steps a-e to do swaps in both layers until one of the layers is solved.</font>
</li><li><font face="Arial" size="2">Find any adjacent pair in the remaining layer that must be swapped.</font>
</li><li><font face="Arial" size="2">Turn the layer to bring it to the front.</font>
</li><li><font face="Arial" size="2">Do the sequence of step e. This temporarily disturbs two pieces in the solved layer.</font>
</li><li><font face="Arial" size="2">Repeat steps g-i for another pair, and this will also restore the temporarily swappes pieces.</font>
</li><li><font face="Arial" size="2">Continue repeating g-i until either both layers are solved, or until one of the layers apparently needs a single swap.</font>
</li><li><font face="Arial" size="2">If one layer apparently needs single swap, it really means that nearly all of them are in the wrong place. Simply pick one of the two 'swapped' pieces, and consider that one to be correct. Then use steps g-j to place the other 7 pieces correct relative to the chosen piece.</font>
</li></ol><p><font face="Arial" size="2"><b>Phase 3:</b> Solve other two layers. <br/>This is the same as phase 2, except as applied to the remaining two layers. Finally, turn all the layers so that they match up.</font></p><p></p> <p>对中间的2 3层不好用</p><p></p>